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在HTML5全栈开发中用十几行代码做贪吃蛇

热度 1已有 734 次阅读2016-5-25 18:04 | 贪吃蛇, HTML5, 开发, 如何

　　教你如何在HTML5全栈开发中用十几行代码做出贪吃蛇，直接上源码：

<!DOCTYPE html>
<html>
<body>
<canvas id="myCanvas" width="240" height="240" style="border:1px solid #d3d3d3;">
Your browser does not support the HTML5 canvas tag.
</canvas>
<script>
var ctx=document.getElementById("myCanvas").getContext("2d"),r = [{x:10,y:9},{x:10,y:8}],co=40,e=null; ctx.shadowBlur=20,ctx.shadowColor="black";
setInterval(function(){
if(check(r[0],0) || r[0].x < 0 || r[0].x >= 24 || r[0].y < 0 || r[0].y >= 24)return;e!=null&&((co==40&&r[0].x==e.x&&r[0].y+1==e.y)||(co==38&&r[0].x==e.x&&r[0].y-1==e.y)||(co==37&&r[0].x-1==e.x&&r[0].y==e.y)||(co==39&&r[0].x+1==e.x&&r[0].y==e.y))?(r.unshift(e),e=null,r.unshift(r.pop())):(r.unshift(r.pop()));
(co==40 || co==38)?(r[0].x=r[1].x,r[0].y=r[1].y+(co==40?1:-1)):(r[0].x=r[1].x+(co==39?1:-1),r[0].y=r[1].y);
ctx.clearRect(0,0,240,240);
if(e)ctx.fillRect(e.x*10,e.y*10,10,10);
for(var i=0;i<r.length;i++)ctx.fillRect(r[i].x*10,r[i].y*10,10,10);
while(e==null || check(e))e={y:(Math.random()*24 >>>0),x:(Math.random()*24 >>>0)};
if(check(r[0],0) || r[0].x < 0 || r[0].x >= 24 || r[0].y < 0 || r[0].y >= 24)alert("game over\nYou get ["+(r.length-2)+"]"); },100);
document.onkeyup = function(event){co=event.keyCode>=37 && event.keyCode<=40 && (Math.abs(event.keyCode-co) != 2)?event.keyCode:co;}
function check(e,j){ for(var i=0;i<r.length;i++)if(j!=i && r[i].x==e.x && r[i].y==e.y)return true; return false;}
</script>
</body>
</html>